Difference between revisions of "031 Review Part 2, Problem 9"
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<span class="exam">If <math style="vertical-align: 0px">A</math> is an <math style="vertical-align: 0px">n\times n</math> matrix such that <math style="vertical-align: -4px">AA^T=I,</math> what are the possible values of <math style="vertical-align: 0px">\text{det }A?</math> | <span class="exam">If <math style="vertical-align: 0px">A</math> is an <math style="vertical-align: 0px">n\times n</math> matrix such that <math style="vertical-align: -4px">AA^T=I,</math> what are the possible values of <math style="vertical-align: 0px">\text{det }A?</math> | ||
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
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|'''1.''' <math style="vertical-align: -5px">\text{det }(AB)=(\text{det }A)(\text{det }B)</math> | |'''1.''' <math style="vertical-align: -5px">\text{det }(AB)=(\text{det }A)(\text{det }B)</math> | ||
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− | |'''2.''' <math style="vertical-align: 0px">\text{det }I= | + | |'''2.''' <math style="vertical-align: 0px">\text{det }I=1</math> |
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|'''3.''' <math style="vertical-align: 0px">\text{det }A^T=\text{det }A</math> | |'''3.''' <math style="vertical-align: 0px">\text{det }A^T=\text{det }A</math> | ||
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| <math>\text{det }A=\pm 1</math> | | <math>\text{det }A=\pm 1</math> | ||
|} | |} | ||
− | [[031_Review_Part_2|'''<u>Return to | + | [[031_Review_Part_2|'''<u>Return to Review Problems</u>''']] |
Latest revision as of 13:40, 15 October 2017
If is an matrix such that what are the possible values of
Foundations: |
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Recall: |
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3. |
Solution:
Step 1: |
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Using the facts in the Foundations section, we have |
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Step 2: |
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Taking the square root of both sides of the equation |
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we obtain |
Final Answer: |
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