Compute
(a) lim n → ∞ 3 − 2 n 2 5 n 2 + n + 1 {\displaystyle \lim _{n\rightarrow \infty }{\frac {3-2n^{2}}{5n^{2}+n+1}}}
(b) lim n → ∞ ln n ln 3 n {\displaystyle \lim _{n\rightarrow \infty }{\frac {\ln n}{\ln 3n}}}
Solution
Detailed Solution
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