Simplify. Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{3x + 6} - \frac{x}{x^2-4} + \frac{3}{x-2}}
| Foundations
|
| How do you simplify Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{x}+\frac{1}{x+2}}
into one fraction?
|
| Answer:
|
| You need to get a common denominator. The common denominator is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x(x+2)}
. So,
|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{x}+\frac{1}{x+2}=\frac{x+2}{x(x+2)}+\frac{x}{x(x+2)}=\frac{2x+2}{x(x+2)}}
.
|
Solution:
| Step 1:
|
| If we factor the denominators, we have Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{3(x+2)} - \frac{x}{(x+2)(x-2)} + \frac{3}{x-2}}
.
|
| So, the common denominator of these three fractions is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3(x-2)(x+2)}
.
|
| Step 2:
|
| So, we have Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{3(x+2)} - \frac{x}{(x+2)(x-2)} + \frac{3}{x-2}=\frac{x-2}{3(x-2)(x+2)} - \frac{3x}{3(x+2)(x-2)} + \frac{3(3)(x+2)}{3(x+2)(x-2)}}
.
|
| Step 3:
|
| Now, combining into one fraction, we have Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{x-2-3x+3(3)(x+2)}{3(x-2)(x+2)}=\frac{7x+16}{3(x-2)(x+2)} }
|
| Final Answer:
|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{7x+16}{3(x-2)(x+2)} }
|
Return to Sample Exam