8A F11 Q2

Question: Find f(5) for f(x) given in problem 1.

Note: The function f(x) from problem 1 is: $f(x)=\log _{3}(x+3)-1$

Foundations
How would you find f(5) if f(x) = 2x + 1 instead?
Answer: we replace every occurrence of x with a 5. So f(5) = 2(5) + 1 = 11

Solution:

Step 1:
Replace any occurrence of x by 5, so $f(5)=\log _{3}(5+3)-1=\log _{3}(8)-1$

Final Answer:
$\log _{3}(8)-1$