004 Sample Final A, Problem 16

Solve. ${\sqrt {x-3}}+5=x$

Foundations
1) How do you solve for $x$ in the equation ${\sqrt {x}}=5$?
2) How do you find the zeros of $f(x)=x^{2}+x-6$?
Answer:
1) You square both sides of the equation to get $x=25$.
2) You factor $f(x)=0$ to get $(x+3)(x-2)=0$. From here, we solve to get $x=-3$ or $x=2$.

Solution:

Step 1:

Step 2:

Step 3:

Step 4:

Final Answer:

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