Find
such that the Maclaurin polynomial of degree
of
approximates
within 0.0001 of the actual value.
| Foundations:
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| Taylor's Theorem
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Let be a function whose th derivative exists on an interval and let be in
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Then, for each in there exists between and such that
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where
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Also,
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Solution:
| Step 1:
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Using Taylor's Theorem, we have that the error in approximating with
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the Maclaurin polynomial of degree is where
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| Step 2:
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| We note that
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle |f^{n+1}(z)|=|\cos(z)|\leq 1}
or
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| Therefore, we have
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| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\bigg |}R_{n}{\bigg (}{\frac {\pi }{3}}{\bigg )}{\bigg |}\leq {\frac {1}{(n+1)!}}{\bigg (}{\frac {\pi }{3}}{\bigg )}^{n+1}.}
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| Now, we have the following table.
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \approx {\frac {1}{(n+1)!}}{\bigg (}{\frac {\pi }{3}}{\bigg )}^{n+1}}
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0.191396}
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0.050107}
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0.01049}
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0.000274}
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Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0.0000358}
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So, is the smallest value of where the error is less than or equal to 0.0001.
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Therefore, for the Maclaurin polynomial approximates within 0.0001 of the actual value.
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| Final Answer:
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