Difference between revisions of "Subsets"
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== Definition == | == Definition == | ||
Let <math>X</math> and <math>Y</math> be sets. We say that '''''<math>X</math> is a subset of <math>Y</math>''''' if every element of <math>X</math> is also an element of <math>Y</math> , and we write <math>X\subseteq Y</math> or <math>Y\supseteq X</math> . Symbolically, <math>X\subseteq Y</math> means <math>x\in X</math> <math>\Rightarrow</math> <math>x\in Y</math> . | Let <math>X</math> and <math>Y</math> be sets. We say that '''''<math>X</math> is a subset of <math>Y</math>''''' if every element of <math>X</math> is also an element of <math>Y</math> , and we write <math>X\subseteq Y</math> or <math>Y\supseteq X</math> . Symbolically, <math>X\subseteq Y</math> means <math>x\in X</math> <math>\Rightarrow</math> <math>x\in Y</math> . | ||
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We want to show that for any <math>x\in X</math> we also have <math>x\in Y</math>. To do this we will let <math>x</math> be an arbitrary element of the set <math>X</math>. This means that <math>x</math> can be written as <math>x=6k</math> for some integer <math>k</math>. Now we wish to show that <math>x=6k</math> is an element of the set <math>Y</math>. To do this, we need to show that our <math>x</math> satisfies the definition of being an element of <math>Y</math>; that is, <math>x</math> must look like <math>2n</math> for some integer <math>n</math>. This can be seen by writing <math>x=6k=2(3k)=2n</math> and declaring <math>3k=n</math>. | We want to show that for any <math>x\in X</math> we also have <math>x\in Y</math>. To do this we will let <math>x</math> be an arbitrary element of the set <math>X</math>. This means that <math>x</math> can be written as <math>x=6k</math> for some integer <math>k</math>. Now we wish to show that <math>x=6k</math> is an element of the set <math>Y</math>. To do this, we need to show that our <math>x</math> satisfies the definition of being an element of <math>Y</math>; that is, <math>x</math> must look like <math>2n</math> for some integer <math>n</math>. This can be seen by writing <math>x=6k=2(3k)=2n</math> and declaring <math>3k=n</math>. | ||
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+ | == Writing Proofs == | ||
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+ | '''How to write a proof that <math>X\subseteq Y</math>''': In general, to show <math>X\subseteq Y</math> we wish to show that if <math>x\in X</math>, then <math>x\in Y</math>. This is done in the following format: | ||
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+ | Let <math>x\in X</math>. ''(logical argument)'', thus <math>x\in Y</math>. This shows that <math>X\subseteq Y</math>. | ||
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+ | The logical argument portion often begins by giving the definition of <math>x\in X</math> and ends with the definition of <math>x\in Y</math>. | ||
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+ | The following is a write-up of the solution of Example 1 as a formal proof: | ||
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+ | Let <math>x\in X</math>. That is, there exists some <math>k\in\mathbb{Z}</math> such that <math>x=6k</math>. We have <math>x=6k=2(3k)</math>. Since <math>3k\in\mathbb{Z}</math>, we also have that <math>x=2n</math> for an integer <math>n</math>, thus <math>x\in Y</math>. This shows that <math>X\subseteq Y</math>. |
Revision as of 12:32, 29 June 2015
Definition
Let and be sets. We say that is a subset of if every element of is also an element of , and we write or . Symbolically, means .
Two sets and are said to be equal, , if both and . Note that some authors use the symbol in place of the symbol .
Example
Show that the set is a subset of
Solution
We want to show that for any we also have . To do this we will let be an arbitrary element of the set . This means that can be written as for some integer . Now we wish to show that is an element of the set . To do this, we need to show that our satisfies the definition of being an element of ; that is, must look like for some integer . This can be seen by writing and declaring .
Writing Proofs
How to write a proof that : In general, to show we wish to show that if , then . This is done in the following format:
Let . (logical argument), thus . This shows that .
The logical argument portion often begins by giving the definition of and ends with the definition of .
The following is a write-up of the solution of Example 1 as a formal proof:
Let . That is, there exists some such that . We have . Since , we also have that for an integer , thus . This shows that .