Difference between revisions of "005 Sample Final A, Question 5"
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|We start by subtracting 2 from each side to get <math>\frac{3x + 5}{x + 2} - \frac{2x + 4}{x + 2} = \frac{x + 1}{x + 2} \ge 0</math> | |We start by subtracting 2 from each side to get <math>\frac{3x + 5}{x + 2} - \frac{2x + 4}{x + 2} = \frac{x + 1}{x + 2} \ge 0</math> | ||
+ | |} | ||
+ | |||
+ | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
+ | ! Step 2: | ||
+ | |- | ||
+ | |<table border="1" cellspacing="0" cellpadding="6" align = "center"> | ||
+ | <tr> | ||
+ | <td align = "center"><math> x:</math></td> | ||
+ | <td align = "center"><math> x<-1 </math></td> | ||
+ | <td align = "center"><math> x=-1 </math></td> | ||
+ | <td align = "center"><math> -1<x<2 </math></td> | ||
+ | <td align = "center"><math> x=2 </math></td> | ||
+ | <td align = "center"><math>x>2</math></td> | ||
+ | </tr> | ||
+ | <tr> | ||
+ | <td align = "center"><math> Sign: </math></td> | ||
+ | <td align = "center"><math> (+) </math></td> | ||
+ | <td align = "center"><math> 0 </math></td> | ||
+ | <td align = "center"><math> (-) </math></td> | ||
+ | <td align = "center"><math> 0 </math></td> | ||
+ | <td align = "center"><math> (+)</math></td> | ||
+ | </tr> | ||
+ | </table> | ||
|} | |} | ||
Revision as of 21:24, 21 May 2015
Question Solve the following inequality. Your answer should be in interval notation.
Step 1: |
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We start by subtracting 2 from each side to get |
Step 2: | ||||||||||||
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Final Answer: |
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