Difference between revisions of "005 Sample Final A, Question 10"
Jump to navigation
Jump to search
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{x+2}{x^3-2x^2+x}}
Kayla Murray (talk | contribs) |
|||
| Line 33: | Line 33: | ||
| To solve for <math>B</math>, we plug in <math>A=2</math> and <math>C=3</math> and simplify. We have | | To solve for <math>B</math>, we plug in <math>A=2</math> and <math>C=3</math> and simplify. We have | ||
|- | |- | ||
| − | |<math>x+2=2(x-1)^2+B(x)(x-1)+3x=2x^2-4x+2+Bx^2-Bx+3x. So, <math>x+2=(2+B)x^2+(-1-B)x+2</math>. Since both sides are equal, | + | |<math>x+2=2(x-1)^2+B(x)(x-1)+3x=2x^2-4x+2+Bx^2-Bx+3x</math>. So, <math>x+2=(2+B)x^2+(-1-B)x+2</math>. Since both sides are equal, |
|- | |- | ||
|we must have <math>2+B=0</math> and <math>-1-B=1</math>. So, <math>B=2</math>. Thus, the decomposition is <math>\frac{x+2}{x(x-1)^2}=\frac{2}{x}+\frac{2}{x-1}+\frac{3}{(x-1)^2}</math>. | |we must have <math>2+B=0</math> and <math>-1-B=1</math>. So, <math>B=2</math>. Thus, the decomposition is <math>\frac{x+2}{x(x-1)^2}=\frac{2}{x}+\frac{2}{x-1}+\frac{3}{(x-1)^2}</math>. | ||
Revision as of 21:46, 19 May 2015
Question Write the partial fraction decomposition of the following,
| Step 1: |
|---|
| First, we factor the denominator. We have |
| Step 2: |
|---|
| Since we have a repeated factor in the denominator, we set . |
| Step 3: |
|---|
| Multiplying both sides of the equation by the denominator , we get |
| . |
| Step 4: |
|---|
| If we let , we get . If we let , we get . |
| Step 5: |
|---|
| To solve for , we plug in and and simplify. We have |
| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x+2=2(x-1)^{2}+B(x)(x-1)+3x=2x^{2}-4x+2+Bx^{2}-Bx+3x} . So, . Since both sides are equal, |
| we must have Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2+B=0} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -1-B=1} . So, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B=2} . Thus, the decomposition is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{x+2}{x(x-1)^2}=\frac{2}{x}+\frac{2}{x-1}+\frac{3}{(x-1)^2}} . |
| Final Answer: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{x+2}{x(x-1)^2}=\frac{2}{x}+\frac{2}{x-1}+\frac{3}{(x-1)^2}} |