Difference between revisions of "005 Sample Final A, Question 4"
Jump to navigation
Jump to search
| Line 11: | Line 11: | ||
|- | |- | ||
| Now we have to solve for y: | | Now we have to solve for y: | ||
| − | <math> \begin{array}{rcl} | + | ::<math> \begin{array}{rcl} |
x & = & \frac{3y}{2y-1}\\ | x & = & \frac{3y}{2y-1}\\ | ||
x(2y - 1) & = & 3y\\ | x(2y - 1) & = & 3y\\ | ||
| Line 18: | Line 18: | ||
y(2x - 3) & = & x\\ | y(2x - 3) & = & x\\ | ||
y & = & \frac{x}{2x - 3} | y & = & \frac{x}{2x - 3} | ||
| − | </math> | + | \end{array}</math> |
| + | |} | ||
| + | |||
| + | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Final Answer: | ||
| + | |- | ||
| + | | y = <math>\frac{x}{2x-3}</math> | ||
|} | |} | ||
Revision as of 18:43, 10 May 2015
Question Find the inverse of the following function
| Step 1: |
|---|
| Switch f(x) for y, to get Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y = \frac{3x}{2x-1}} , then switch y and x to get Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x = \frac{3y}{2y-1}} |
| Step 2: |
|---|
Now we have to solve for y:
|
| Final Answer: |
|---|
| y = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{x}{2x-3}} |