Difference between revisions of "005 Sample Final A, Question 2"

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Line 32: Line 32:
 
     <td align = "center"><math> x<-1 </math></td>
 
     <td align = "center"><math> x<-1 </math></td>
 
     <td align = "center"><math> x=-1 </math></td>
 
     <td align = "center"><math> x=-1 </math></td>
     <td align = "center"><math> -1<x<5 </math></td>
+
     <td align = "center"><math> -1<x<2 </math></td>
     <td align = "center"><math> x=5 </math></td>
+
     <td align = "center"><math> x=2 </math></td>
     <td align = "center"><math>x>5</math></td>
+
     <td align = "center"><math>x>2</math></td>
 
   </tr>
 
   </tr>
 
   <tr>
 
   <tr>
     <td align = "center"><math> f'(x):</math></td>
+
     <td align = "center"><math> Sign:</math></td>
 
     <td align = "center"><math> (+) </math></td>
 
     <td align = "center"><math> (+) </math></td>
 
     <td align = "center"><math> 0 </math></td>
 
     <td align = "center"><math> 0 </math></td>

Revision as of 10:43, 6 May 2015

Question Find the domain of the following function. Your answer should be in interval notation

Foundations:
1) What is the domain of ?
2) How can we factor ?
Answer:
1) The domain is . The domain of is , but we have to remove zero from the domain since we cannot divide by 0.
2)


Step 1:
We start by factoring into
Step 1:
Since we cannot divide by zero, and we cannot take the square root of a negative number, we use a sign chart to determine when