Difference between revisions of "004 Sample Final A, Problem 6"
Jump to navigation
Jump to search
Kayla Murray (talk | contribs) |
Kayla Murray (talk | contribs) |
||
| Line 3: | Line 3: | ||
! Foundations | ! Foundations | ||
|- | |- | ||
| − | | | + | |How do you simplify <math>\frac{1}{x}+\frac{1}{x+2}</math> into one fraction? |
|- | |- | ||
|Answer: | |Answer: | ||
|- | |- | ||
| − | | | + | |You need to get a common denominator. The common denominator is <math>x(x+2)</math>. So, |
| + | |- | ||
| + | |<math>\frac{1}{x}+\frac{1}{x+2}=\frac{x+2}{x(x+2)}+\frac{x}{x(x+2)}=\frac{2x+2}{x(x+2)}</math>. | ||
|} | |} | ||
Revision as of 15:45, 4 May 2015
Simplify.
| Foundations |
|---|
| How do you simplify into one fraction? |
| Answer: |
| You need to get a common denominator. The common denominator is . So, |
| . |
Solution:
| Step 1: |
|---|
| Step 2: |
|---|
| Step 3: |
|---|
| Step 4: |
|---|
| Final Answer: |
|---|