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| − | |We have to make sure the answers make sense in the context of the problem. Since the domain of the log function is <math> (0, \infty)</math>, -3 is removed as a potential answer. | + | |We have to make sure the answers make sense in the context of the problem. Since the domain of the log function is <math> (0, \infty)</math>, -3 is removed as a potential answer. |
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Revision as of 23:07, 13 April 2015
Question: Solve.
| Foundations
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| 1) How do we combine the two logs?
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| 2) How do we remove the logs?
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| Answer:
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| 1) One of the rules of logarithms says that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \log(x) + \log(y) = \log(xy)}
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| 2) The definition of logarithm tells us that if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \log_6(x) = y }
, then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 6^y = x }
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Solution:
| Step 1:
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| Using a rule of logarithms the left hand side is equal to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \log_6( (x + 2)(x - 3)}
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| Step 2:
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| By the definition of logarithms Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \log_6( (x + 2)(x - 3) = 1}
means Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 6 = (x + 2)(x - 3)}
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| Step 3:
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| Now we do some arithmetic to solve for x. Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 0 = (x + 2)(x - 3) - 6 = x^2 - x - 12 = (x - 4)(x + 3) }
. So there are two possible answers.
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| Step 4:
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| We have to make sure the answers make sense in the context of the problem. Since the domain of the log function is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (0, \infty)}
, -3 is removed as a potential answer.
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