Difference between revisions of "031 Review Part 2, Problem 7"
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 1: | !Step 1: | ||
| + | |- | ||
| + | |We claim that <math>T</math> is not a linear transformation. | ||
| + | |- | ||
| + | |Consider the vectors <math>\begin{bmatrix} | ||
| + | 1\\ | ||
| + | 0 | ||
| + | \end{bmatrix}</math> and <math>\begin{bmatrix} | ||
| + | 0\\ | ||
| + | 1 | ||
| + | \end{bmatrix}.</math> | ||
| + | |- | ||
| + | |Then, we have | ||
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{T\bigg(\begin{bmatrix} | ||
| + | 1\\ | ||
| + | 0 | ||
| + | \end{bmatrix}+\begin{bmatrix} | ||
| + | 0\\ | ||
| + | 1 | ||
| + | \end{bmatrix}\bigg)} & = & \displaystyle{T\bigg(\begin{bmatrix} | ||
| + | 1\\ | ||
| + | 1 | ||
| + | \end{bmatrix}\bigg)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\begin{bmatrix} | ||
| + | 0\\ | ||
| + | 2 | ||
| + | \end{bmatrix}.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 2: | !Step 2: | ||
| + | |- | ||
| + | |On the other hand, notice | ||
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{T\bigg(\begin{bmatrix} | ||
| + | 1\\ | ||
| + | 0 | ||
| + | \end{bmatrix}+\begin{bmatrix} | ||
| + | 0\\ | ||
| + | 1 | ||
| + | \end{bmatrix}\bigg)} & = & \displaystyle{T\bigg(\begin{bmatrix} | ||
| + | 1\\ | ||
| + | 1 | ||
| + | \end{bmatrix}\bigg)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\begin{bmatrix} | ||
| + | 0\\ | ||
| + | 2 | ||
| + | \end{bmatrix}.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
Revision as of 12:30, 12 October 2017
(a) Let be a transformation given by
Determine whether is a linear transformation. Explain.
(b) Let and Find Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle AB,~BA^T} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A-B^T.}
| Foundations: |
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| A map Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T:\mathbb{R}^n\rightarrow \mathbb{R}^m} is a linear transformation if |
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Solution:
(a)
| Step 1: |
|---|
| We claim that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T} is not a linear transformation. |
| Consider the vectors Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{bmatrix} 1\\ 0 \end{bmatrix}} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{bmatrix} 0\\ 1 \end{bmatrix}.} |
| Then, we have |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{T\bigg(\begin{bmatrix} 1\\ 0 \end{bmatrix}+\begin{bmatrix} 0\\ 1 \end{bmatrix}\bigg)} & = & \displaystyle{T\bigg(\begin{bmatrix} 1\\ 1 \end{bmatrix}\bigg)}\\ &&\\ & = & \displaystyle{\begin{bmatrix} 0\\ 2 \end{bmatrix}.} \end{array}} |
| Step 2: |
|---|
| On the other hand, notice |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{T\bigg(\begin{bmatrix} 1\\ 0 \end{bmatrix}+\begin{bmatrix} 0\\ 1 \end{bmatrix}\bigg)} & = & \displaystyle{T\bigg(\begin{bmatrix} 1\\ 1 \end{bmatrix}\bigg)}\\ &&\\ & = & \displaystyle{\begin{bmatrix} 0\\ 2 \end{bmatrix}.} \end{array}} |
(b)
| Step 1: |
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| Step 2: |
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| Final Answer: |
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| (a) |
| (b) |