Difference between revisions of "031 Review Part 2, Problem 11"
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Foundations: | !Foundations: | ||
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+ | |'''1.''' To solve a system of equations, we turn the system into an augmented matrix and | ||
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+ | ::row reduce that matrix to determine the solution. | ||
+ | |- | ||
+ | |'''2.''' For a system to have a unique solution, we need to have no free variables. | ||
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Revision as of 10:49, 10 October 2017
Consider the following system of equations.
Find all real values of such that the system has only one solution.
Foundations: |
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1. To solve a system of equations, we turn the system into an augmented matrix and |
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2. For a system to have a unique solution, we need to have no free variables. |
Solution:
Step 1: |
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Step 2: |
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Final Answer: |
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