Difference between revisions of "8A F11 Q7"
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(Created page with "'''Question:''' Solve <math>2\vert 3x-4\vert -7 = 7</math> {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundations |- |1) How...") |
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|Now we solve both equations. The first leads to the solution <math>x = \frac{11}{3}</math>. The second leads to <math>x = -1</math> | |Now we solve both equations. The first leads to the solution <math>x = \frac{11}{3}</math>. The second leads to <math>x = -1</math> | ||
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| + | [[8AF11Final|<u>'''Return to Sample Exam</u>''']] | ||
Revision as of 15:26, 6 April 2015
Question: Solve
| Foundations |
|---|
| 1) How do we get to the first key step in solving any function involving absolute value equations? |
| 2) How do we solve absolute value equations? |
| Answer: |
| 1) We isolate everything inside of the absolute value signs. |
| 2) We create two equations based on whether the expression inside the absolute value is positive or negative. |
| Then we solve both equations. |
Solution:
| Step 1: |
|---|
| Isolate the absolute values. First by adding 7 to both sides, then dividing both sides by 2. |
| This leads to |
| Step 2: |
|---|
| Now we create two equations: and . |
| Step 3: |
|---|
| Now we solve both equations. The first leads to the solution . The second leads to |