Difference between revisions of "009A Sample Final 3, Problem 5"
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!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |Therefore, the slope of the tangent line at the point <math style="vertical-align: -5px">(1,1)</math> is |
|- | |- | ||
| − | | | + | | <math>\begin{array}{rcl} |
| + | \displaystyle{m} & = & \displaystyle{\frac{3(1)^2-2(1)}{2(1)-3(1)^2}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\frac{3-2}{2-3}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{-1.} | ||
| + | \end{array}</math> | ||
| + | |- | ||
| + | |Hence, the equation of the tangent line to the curve at the point <math style="vertical-align: -5px">(1,1)</math> is | ||
| + | |- | ||
| + | | <math>f(x)=-1(x-1)+1.</math> | ||
|} | |} | ||
| Line 44: | Line 54: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | | | + | | <math>f(x)=-1(x-1)+1</math> |
|} | |} | ||
[[009A_Sample_Final_3|'''<u>Return to Sample Exam</u>''']] | [[009A_Sample_Final_3|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 11:01, 6 March 2017
Calculate the equation of the tangent line to the curve defined by at the point, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (1,1).}
| Foundations: |
|---|
| The equation of the tangent line to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} at the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a,b)} is |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y=m(x-a)+b} where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle m=f'(a).} |
Solution:
| Step 1: |
|---|
| We use implicit differentiation to find the derivative of the given curve. |
| Using the product and chain rule, we get |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3x^2+3y^2y'=2y+2xy'.} |
| We rearrange the terms and solve for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y'.} |
| Therefore, |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3x^2-2y=2xy'-3y^2y'} |
| and |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y'=\frac{3x^2-2y}{2x-3y^2}.} |
| Step 2: |
|---|
| Therefore, the slope of the tangent line at the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (1,1)} is |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{m} & = & \displaystyle{\frac{3(1)^2-2(1)}{2(1)-3(1)^2}}\\ &&\\ & = & \displaystyle{\frac{3-2}{2-3}}\\ &&\\ & = & \displaystyle{-1.} \end{array}} |
| Hence, the equation of the tangent line to the curve at the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (1,1)} is |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)=-1(x-1)+1.} |
| Final Answer: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)=-1(x-1)+1} |