Difference between revisions of "009A Sample Final 3, Problem 4"
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!Step 1: | !Step 1: | ||
|- | |- | ||
| − | | | + | |We first calculate <math style="vertical-align: -14px">\lim_{x\rightarrow 0^+}f(x).</math> We have |
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{\lim_{x\rightarrow 0^+}f(x)} & = & \displaystyle{\lim_{x\rightarrow 0^+} x-\cos x}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{0-\cos(0)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{-1.} | ||
| + | \end{array}</math> | ||
| + | |} | ||
| + | |||
| + | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Step 2: | ||
|- | |- | ||
| − | | | + | |Now, we calculate <math style="vertical-align: -14px">\lim_{x\rightarrow 0^-}f(x).</math> We have |
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{\lim_{x\rightarrow 0^-}f(x)} & = & \displaystyle{\lim_{x\rightarrow 0^-} \frac{x}{|x|}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\lim_{x\rightarrow 0^-} \frac{x}{-x}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\lim_{x\rightarrow 0^-} -1}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{-1.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| − | !Step | + | !Step 3: |
| + | |- | ||
| + | |Since | ||
|- | |- | ||
| | | | ||
| + | <math style="vertical-align: -15px">\lim_{x\rightarrow 3^+}f(x)=\lim_{x\rightarrow 3^-}f(x)=-1,</math> | ||
|- | |- | ||
| − | | | + | |we have |
| + | |- | ||
| + | | <math>\lim_{x\rightarrow 3} f(x)=-1.</math> | ||
| + | |- | ||
| + | |But, | ||
| + | |- | ||
| + | | <math>f(0)=0\ne \lim_{x\rightarrow 3} f(x).</math> | ||
| + | |- | ||
| + | |Thus, <math style="vertical-align: -5px">f(x)</math> is not continuous. | ||
| + | |- | ||
| + | |It is a jump discontinuity. | ||
|} | |} | ||
| Line 47: | Line 80: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | | | + | | <math style="vertical-align: -5px">f(x)</math> is not continuous. It is a jump discontinuity. |
|} | |} | ||
[[009A_Sample_Final_3|'''<u>Return to Sample Exam</u>''']] | [[009A_Sample_Final_3|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 11:48, 6 March 2017
Discuss, without graphing, if the following function is continuous at
If you think Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f} is not continuous at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=0,} what kind of discontinuity is it?
| Foundations: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is continuous at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=a} if |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow a^+}f(x)=\lim_{x\rightarrow a^-}f(x)=f(a).} |
Solution:
| Step 1: |
|---|
| We first calculate Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 0^+}f(x).} We have |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\lim_{x\rightarrow 0^+}f(x)} & = & \displaystyle{\lim_{x\rightarrow 0^+} x-\cos x}\\ &&\\ & = & \displaystyle{0-\cos(0)}\\ &&\\ & = & \displaystyle{-1.} \end{array}} |
| Step 2: |
|---|
| Now, we calculate Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 0^-}f(x).} We have |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\lim_{x\rightarrow 0^-}f(x)} & = & \displaystyle{\lim_{x\rightarrow 0^-} \frac{x}{|x|}}\\ &&\\ & = & \displaystyle{\lim_{x\rightarrow 0^-} \frac{x}{-x}}\\ &&\\ & = & \displaystyle{\lim_{x\rightarrow 0^-} -1}\\ &&\\ & = & \displaystyle{-1.} \end{array}} |
| Step 3: |
|---|
| Since |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 3^+}f(x)=\lim_{x\rightarrow 3^-}f(x)=-1,} |
| we have |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 3} f(x)=-1.} |
| But, |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(0)=0\ne \lim_{x\rightarrow 3} f(x).} |
| Thus, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is not continuous. |
| It is a jump discontinuity. |
| Final Answer: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is not continuous. It is a jump discontinuity. |