Difference between revisions of "009B Sample Final 3, Problem 6"
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Kayla Murray (talk | contribs) |
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|First, we factor the denominator to get | |First, we factor the denominator to get | ||
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− | |<math>\int \frac{3x-1}{2x^2-x}~dx=\int \frac{3x-1}{x(2x-1)}.</math> | + | | <math>\int \frac{3x-1}{2x^2-x}~dx=\int \frac{3x-1}{x(2x-1)}.</math> |
|- | |- | ||
|We use the method of partial fraction decomposition. | |We use the method of partial fraction decomposition. | ||
Line 31: | Line 31: | ||
|We let | |We let | ||
|- | |- | ||
− | |<math>\frac{3x-1}{x(2x-1)}=\frac{A}{x}+\frac{B}{2x-1}.</math> | + | | <math>\frac{3x-1}{x(2x-1)}=\frac{A}{x}+\frac{B}{2x-1}.</math> |
|} | |} | ||
Revision as of 13:46, 2 March 2017
Find the following integrals
(a)
(b)
Foundations: |
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Through partial fraction decomposition, we can write the fraction |
for some constants |
Solution:
(a)
Step 1: |
---|
First, we factor the denominator to get |
We use the method of partial fraction decomposition. |
We let |
Step 2: |
---|
(b)
Step 1: |
---|
Step 2: |
---|
Final Answer: |
---|
(a) |
(b) |