Difference between revisions of "009A Sample Midterm 2, Problem 5"
Jump to navigation
Jump to search
Kayla Murray (talk | contribs) |
Kayla Murray (talk | contribs) |
||
Line 25: | Line 25: | ||
|First, we use the Chain Rule to get | |First, we use the Chain Rule to get | ||
|- | |- | ||
− | | <math>f'(x)=3\tan^2( | + | | <math>f'(x)=3\tan^2(7x^2+5)(\tan(7x^2+5))'.</math> |
|} | |} | ||
Line 31: | Line 31: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
− | | | + | |Now, we use the Chain Rule again to get |
|- | |- | ||
| | | | ||
+ | <math>\begin{array}{rcl} | ||
+ | \displaystyle{f'(x)} & = & \displaystyle{3\tan^2(7x^2+5)(\tan(7x^2+5))'}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{3\tan^2(7x^2+5)\sec^2(7x^2+5)(7x^2+5)'}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{3\tan^2(7x^2+5)\sec^2(7x^2+5)(14x).} | ||
+ | \end{array}</math> | ||
|} | |} | ||
Line 90: | Line 97: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
− | |'''(a)''' | + | | '''(a)''' <math>3\tan^2(7x^2+5)\sec^2(7x^2+5)(14x)</math> |
|- | |- | ||
|'''(b)''' | |'''(b)''' |
Revision as of 13:35, 17 February 2017
Find the derivatives of the following functions. Do not simplify.
- a)
- b)
- c)
Foundations: |
---|
1. Chain Rule |
2. Derivatives of trig/ln |
3. Quotient Rule |
Solution:
(a)
Step 1: |
---|
First, we use the Chain Rule to get |
Step 2: |
---|
Now, we use the Chain Rule again to get |
|
(b)
Step 1: |
---|
Step 2: |
---|
(c)
Step 1: |
---|
Step 2: |
---|
Final Answer: |
---|
(a) |
(b) |
(c) |