Difference between revisions of "009A Sample Midterm 2, Problem 5"

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Line 25: Line 25:
 
|First, we use the Chain Rule to get
 
|First, we use the Chain Rule to get
 
|-
 
|-
|&nbsp; &nbsp; &nbsp; &nbsp; <math>f'(x)=3\tan^2(
+
|&nbsp; &nbsp; &nbsp; &nbsp; <math>f'(x)=3\tan^2(7x^2+5)(\tan(7x^2+5))'.</math>
 
|}
 
|}
  
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!Step 2: &nbsp;
 
!Step 2: &nbsp;
 
|-
 
|-
|
+
|Now, we use the Chain Rule again to get
 
|-
 
|-
 
|
 
|
 +
&nbsp; &nbsp; &nbsp; &nbsp; <math>\begin{array}{rcl}
 +
\displaystyle{f'(x)} & = & \displaystyle{3\tan^2(7x^2+5)(\tan(7x^2+5))'}\\
 +
&&\\
 +
& = & \displaystyle{3\tan^2(7x^2+5)\sec^2(7x^2+5)(7x^2+5)'}\\
 +
&&\\
 +
& = & \displaystyle{3\tan^2(7x^2+5)\sec^2(7x^2+5)(14x).}
 +
\end{array}</math>
 
|}
 
|}
  
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!Final Answer: &nbsp;  
 
!Final Answer: &nbsp;  
 
|-
 
|-
|'''(a)'''  
+
|&nbsp; &nbsp; '''(a)''' &nbsp; &nbsp; <math>3\tan^2(7x^2+5)\sec^2(7x^2+5)(14x)</math>
 
|-
 
|-
 
|'''(b)'''
 
|'''(b)'''

Revision as of 13:35, 17 February 2017

Find the derivatives of the following functions. Do not simplify.

a)
b)
c)


Foundations:  
1. Chain Rule
2. Derivatives of trig/ln
3. Quotient Rule


Solution:

(a)

Step 1:  
First, we use the Chain Rule to get
       
Step 2:  
Now, we use the Chain Rule again to get

       

(b)

Step 1:  
Step 2:  

(c)

Step 1:  
Step 2:  


Final Answer:  
    (a)    
(b)
(c)

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