Difference between revisions of "009A Sample Midterm 1, Problem 4"
Jump to navigation
Jump to search
Kayla Murray (talk | contribs) |
Kayla Murray (talk | contribs) |
||
Line 22: | Line 22: | ||
!Step 1: | !Step 1: | ||
|- | |- | ||
− | | | + | |Using the Product Rule, we have |
|- | |- | ||
− | | | + | | <math>f'(x)=(\sqrt{x})'(x^2+2)+\sqrt{x}(x^2+2)'.</math> |
|} | |} | ||
Line 30: | Line 30: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
− | | | + | |Now, we have |
|- | |- | ||
− | | | + | | <math>\begin{array}{rcl} |
+ | \displaystyle{f'(x)} & = & \displaystyle{(\sqrt{x})'(x^2+2)+\sqrt{x}(x^2+2)'}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{\bigg(\frac{1}{2}x^{-\frac{1}{2}}\bigg)(x^2+2)+\sqrt{x}(2x).} | ||
+ | \end{array}</math> | ||
|} | |} | ||
Line 88: | Line 92: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
− | |'''(a)''' | + | | '''(a)''' <math>\bigg(\frac{1}{2}x^{-\frac{1}{2}}\bigg)(x^2+2)+\sqrt{x}(2x)</math> |
|- | |- | ||
|'''(b)''' | |'''(b)''' |
Revision as of 10:22, 16 February 2017
Find the derivatives of the following functions. Do not simplify.
- a)
- b) where
- c)
Foundations: |
---|
1. Product Rule |
2. Quotient Rule |
3. Chain Rule |
Solution:
(a)
Step 1: |
---|
Using the Product Rule, we have |
Step 2: |
---|
Now, we have |
(b)
Step 1: |
---|
Step 2: |
---|
(c)
Step 1: |
---|
Step 2: |
---|
Final Answer: |
---|
(a) |
(b) |
(c) |