Difference between revisions of "009C Sample Midterm 2, Problem 3"

Revision as of 09:32, 5 February 2017

Determine convergence or divergence:

a)

\sum _{n=1}^{\infty }(-1)^{n}{\sqrt {\frac {1}{n}}}

b)

\sum _{n=1}^{\infty }(-2)^{n}{\frac {n!}{n^{n}}}

Solution:

(a)

Step 1:

Step 2:

(b)

Final Answer:
(a)
(b)

@@ Line 1: / Line 1: @@
-<span class="exam">
+<span class="exam">Determine convergence or divergence:
-::<span class="exam">a)
+::<span class="exam">a) <math>\sum_{n=1}^\infty (-1)^n \sqrt{\frac{1}{n}}</math>
-::<span class="exam">b)
+::<span class="exam">b) <math>\sum_{n=1}^\infty (-2)^n \frac{n!}{n^n} </math>