Difference between revisions of "009A Sample Final 1, Problem 6"

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::::::<math>f(x)=3x-2\sin x+7</math>
 
::::::<math>f(x)=3x-2\sin x+7</math>
  
<span class="exam">a) Use the Intermediate Value Theorem to show that <math>f(x)</math> has at least one zero.
+
<span class="exam">a) Use the Intermediate Value Theorem to show that <math style="vertical-align: -3px">f(x)</math> has at least one zero.
  
<span class="exam">b) Use the Mean Value Theorem to show that <math>f(x)</math> has at most one zero.
+
<span class="exam">b) Use the Mean Value Theorem to show that <math style="vertical-align: -3px">f(x)</math> has at most one zero.
  
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"

Revision as of 14:13, 22 February 2016

Consider the following function:

a) Use the Intermediate Value Theorem to show that has at least one zero.

b) Use the Mean Value Theorem to show that has at most one zero.

Foundations:  

Solution:

(a)

Step 1:  
First note that .
Also, .
Since ,
.
Thus, and hence .
Step 2:  
Since and , there exists with such that
by the Intermediate Value Theorem. Hence, has at least one zero.

(b)

Step 1:  
We have . Since ,
. So, .
Therefore, is always positive.
Step 2:  
Since is always positive, is an increasing function.
Thus, has at most one zero.
Final Answer:  
(a) Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(-5)<0} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(0)>0} , there exists Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x} with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -5<x<0} such that
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)=0} by the Intermediate Value Theorem. Hence, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} has at least one zero.
(b) Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x)} is always positive, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is an increasing function.
Thus, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} has at most one zero.

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