Difference between revisions of "Multivariate Calculus 10B, Problem 1"
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− | |Here we use change of variable, <math>\int _0^1 \int_0^x e^{\frac{y}{x}}~dydx = \int _0^1[xe^{\frac{y}{x}}|_{y = 0}^{y = x}]~dx</math> | + | |Here we use change of variable, <math>\int _0^1 \int_0^x e^{\frac{y}{x}}~dydx = \int _0^1[xe^{\frac{y}{x}}|_{y = 0}^{y = x}]~dx = \int_0^1 x(e - 1)~dx</math> |
Revision as of 02:50, 7 February 2016
Calculate the following integrals
- a)
- b)
solution(a):
Here we use change of variable, |