Difference between revisions of "Multivariate Calculus 10B, Problem 1"
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:: <span class="exam">b) <math>\int_0^1 \int_0^{cos^{-1}(y)} e^{2x-y}~dxdy</math> | :: <span class="exam">b) <math>\int_0^1 \int_0^{cos^{-1}(y)} e^{2x-y}~dxdy</math> | ||
− | '''solution: | + | '''solution(a):'' |
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
− | ! | + | ! |
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|Here we use change of variable, <math>\int _0^1 \int_0^x e^{\frac{y}{x}}~dydx = \int _0^1[xe^{\frac{y}{x}}|_{y = 0}^{y = x}]~dx</math> | |Here we use change of variable, <math>\int _0^1 \int_0^x e^{\frac{y}{x}}~dydx = \int _0^1[xe^{\frac{y}{x}}|_{y = 0}^{y = x}]~dx</math> |
Revision as of 02:46, 7 February 2016
Calculate the following integrals
- a)
- b)
'solution(a):
Here we use change of variable, |