Difference between revisions of "Multivariate Calculus 10B, Problem 1"

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:: <span class="exam">b) <math>\int_0^1 \int_0^{cos^{-1}(y)} e^{2x-y}~dxdy</math>
 
:: <span class="exam">b) <math>\int_0^1 \int_0^{cos^{-1}(y)} e^{2x-y}~dxdy</math>
  
'''solution:'''
+
'''solution(a):''
 
 
'''a'''
 
  
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
!Step 1: &nbsp;
+
!  
 
|-
 
|-
 
|Here we use change of variable, <math>\int _0^1 \int_0^x e^{\frac{y}{x}}~dydx = \int _0^1[xe^{\frac{y}{x}}|_{y = 0}^{y = x}]~dx</math>
 
|Here we use change of variable, <math>\int _0^1 \int_0^x e^{\frac{y}{x}}~dydx = \int _0^1[xe^{\frac{y}{x}}|_{y = 0}^{y = x}]~dx</math>

Revision as of 02:46, 7 February 2016

Calculate the following integrals

a)
b)

'solution(a):

Here we use change of variable,