Difference between revisions of "009B Sample Midterm 1, Problem 3"
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!Step 1: | !Step 1: | ||
|- | |- | ||
| − | | | + | |We proceed using integration by parts. Let <math>u=x^2</math> and <math>dv=e^xdx</math>. Then, <math>du=2xdx</math> and <math>v=e^x</math>. |
| + | |- | ||
| + | |Therefore, we have | ||
|- | |- | ||
| − | | | + | |<math>\int x^2 e^xdx=x^2e^x-\int 2xdx</math> |
|} | |} | ||
| Line 25: | Line 27: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |Now, we need to use integration by parts again. Let <math>u=2x</math> and <math>dv=e^xdx</math>. Then, <math>du=2dx</math> and <math>v=e^x</math>. |
| + | |- | ||
| + | |Therefore, we have | ||
|- | |- | ||
| − | | | + | |<math>\int x^2 e^xdx=x^2e^x-\bigg(2xe^x-\int 2e^xdx\bigg)=x^2e^x-2xe^x+2e^x+C</math> |
|} | |} | ||
| Line 58: | Line 62: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | |'''(a)''' | + | |'''(a)''' <math>x^2e^x-2xe^x+2e^x+C</math> |
|- | |- | ||
|'''(b)''' | |'''(b)''' | ||
|} | |} | ||
[[009B_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']] | [[009B_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 12:08, 31 January 2016
Evaluate the indefinite and definite integrals.
- a)
- b)
| Foundations: |
|---|
| Review integration by parts |
Solution:
(a)
| Step 1: |
|---|
| We proceed using integration by parts. Let and . Then, and . |
| Therefore, we have |
| Step 2: |
|---|
| Now, we need to use integration by parts again. Let and . Then, and . |
| Therefore, we have |
(b)
| Step 1: |
|---|
| Step 2: |
|---|
| Final Answer: |
|---|
| (a) |
| (b) |