Difference between revisions of "022 Sample Final A, Problem 3"

From Grad Wiki
Jump to navigation Jump to search
Line 17: Line 17:
 
|-
 
|-
 
|3) We have to remember that <math>\int \frac{c}{x - a} dx = c\ln(x - a)</math>&nbsp;, for any numbers c, a.
 
|3) We have to remember that <math>\int \frac{c}{x - a} dx = c\ln(x - a)</math>&nbsp;, for any numbers c, a.
 +
|}
 +
 +
'''Solution:'''
 +
 +
{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
 +
!Step 1: &nbsp;
 +
|-
 +
|First, we factor <math>x^2 - x - 12 = (x - 4)(x + 3)</math>
 +
|}
 +
 +
{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
 +
!Step 2: &nbsp;
 +
|-
 +
|Now we want to find the partial fraction expansion for <math>\frac{6}{(x - 4)(x + 3)}</math>&nbsp;, which will have the form <math>\frac{A}{x - 4} + {B}{x + 3}</math>
 +
|-
 +
|To do this we need to solve the equation <math>6 = A( x + 3) + B(x - 4)</math>
 +
|-
 +
|Plugging in -3 for x to both sides we find that <math>6 = -7B</math> &nbsp; and &nbsp; <math>B = -\frac{6}{7}</math>.
 +
|-
 +
|Now we can find A by plugging in 4 for x to both sides. This yields <math>6 = 7A</math>&nbsp;, so <math>A = \frac{6}{7}</math>
 +
|-
 +
|Finally we have the partial fraction expansion: <math>\frac{6}{x^2 -x - 12} = \frac{6}{7(x - 4)} - \frac{6}{7(x + 3)}</math>
 
|}
 
|}

Revision as of 11:43, 30 May 2015

Find the antiderivative: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int \frac{6}{x^2 - x - 12}}

Foundations:  
1) What does the denominator factor into? What will be the form of the decomposition?
2) How do you solve for the numerators?
3) What special integral do we have to use?
Answer:
1) Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x^2 - x - 12 = (x - 4)(x +3)}  , and each term has multiplicity one, the decomposition will be of the form: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{A}{x - 4} + \frac{B}{x + 3}}
2) After writing the equality, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{6}{x^2 -x - 12} = \frac{A}{x - 4} + \frac{B}{x + 3}} , clear the denominators, and evaluate both sides at x = 4, -3, Each evaluation will yield the value of one of the unknowns.
3) We have to remember that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int \frac{c}{x - a} dx = c\ln(x - a)}  , for any numbers c, a.

Solution:

Step 1:  
First, we factor Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x^2 - x - 12 = (x - 4)(x + 3)}
Step 2:  
Now we want to find the partial fraction expansion for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{6}{(x - 4)(x + 3)}}  , which will have the form Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{A}{x - 4} + {B}{x + 3}}
To do this we need to solve the equation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 6 = A( x + 3) + B(x - 4)}
Plugging in -3 for x to both sides we find that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 6 = -7B}   and   Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B = -\frac{6}{7}} .
Now we can find A by plugging in 4 for x to both sides. This yields Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 6 = 7A}  , so Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A = \frac{6}{7}}
Finally we have the partial fraction expansion: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{6}{x^2 -x - 12} = \frac{6}{7(x - 4)} - \frac{6}{7(x + 3)}}
Retrieved from "https://gradwiki.math.ucr.edu/index.php?title=022_Sample_Final_A,_Problem_3&oldid=839"