Difference between revisions of "005 Sample Final A, Question 5"

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|We start by subtracting 2 from each side to get <math>\frac{3x + 5}{x + 2} - \frac{2x + 4}{x + 2} = \frac{x + 1}{x + 2} \ge 0</math>
 
|We start by subtracting 2 from each side to get <math>\frac{3x + 5}{x + 2} - \frac{2x + 4}{x + 2} = \frac{x + 1}{x + 2} \ge 0</math>
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! Final Answer:
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|<math>(-\infty, -2)\cup[1, \infty)</math>
 
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Revision as of 15:04, 17 May 2015

Question Solve the following inequality. Your answer should be in interval notation.


Step 1:
We start by subtracting 2 from each side to get


Final Answer: