Difference between revisions of "004 Sample Final A, Problem 6"

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|How do you simplify <math>\frac{1}{x}+\frac{1}{x+2}</math> into one fraction?
 
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|You need to get a common denominator. The common denominator is <math>x(x+2)</math>. So,
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|<math>\frac{1}{x}+\frac{1}{x+2}=\frac{x+2}{x(x+2)}+\frac{x}{x(x+2)}=\frac{2x+2}{x(x+2)}</math>.
 
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Revision as of 14:45, 4 May 2015

Simplify.      Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{3x + 6} - \frac{x}{x^2-4} + \frac{3}{x-2}}

Foundations
How do you simplify Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{x}+\frac{1}{x+2}} into one fraction?
Answer:
You need to get a common denominator. The common denominator is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x(x+2)} . So,
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{1}{x}+\frac{1}{x+2}=\frac{x+2}{x(x+2)}+\frac{x}{x(x+2)}=\frac{2x+2}{x(x+2)}} .


Solution:

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Final Answer:

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