Difference between revisions of "031 Review Part 3, Problem 7"

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{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 2:  
 
!Step 2:  
 +
|-
 +
|By the Diagonalization Theorem, a basis for the eigenspace corresponding
 +
|-
 +
|to the eigenvalue &nbsp;<math style="vertical-align: 0px">3</math>&nbsp; is
 +
|-
 +
|
 +
::<math>\Bigg\{\begin{bmatrix}
 +
          3 \\
 +
          0 \\
 +
          1
 +
        \end{bmatrix},\begin{bmatrix}
 +
          -1 \\
 +
          -3\\
 +
          0
 +
        \end{bmatrix}\Bigg\}</math>
 +
|-
 +
|and a basis for the eigenspace corresponding to the eigenvalue &nbsp;<math style="vertical-align: -1px">4</math>&nbsp; is
 
|-
 
|-
 
|
 
|
 +
::<math>\Bigg\{\begin{bmatrix}
 +
          0 \\
 +
          1 \\
 +
          1
 +
        \end{bmatrix}\Bigg\}.</math>
 
|}
 
|}
  
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!Final Answer: &nbsp;  
 
!Final Answer: &nbsp;  
 
|-
 
|-
|&nbsp;&nbsp; &nbsp; &nbsp;  
+
|&nbsp; &nbsp; &nbsp; &nbsp; The eigenvalues of &nbsp;<math style="vertical-align: 0px">A</math>&nbsp; are &nbsp;<math style="vertical-align: 0px">3</math>&nbsp; and &nbsp;<math style="vertical-align: -1px">4.</math>&nbsp;
 +
|-
 +
|&nbsp; &nbsp; &nbsp; &nbsp; A basis for the eigenspace corresponding
 +
|-
 +
|&nbsp; &nbsp; &nbsp; &nbsp; to the eigenvalue &nbsp;<math style="vertical-align: 0px">3</math>&nbsp; is
 +
|-
 +
|
 +
::::<math>\Bigg\{\begin{bmatrix}
 +
          3 \\
 +
          0 \\
 +
          1
 +
        \end{bmatrix},\begin{bmatrix}
 +
          -1 \\
 +
          -3\\
 +
          0
 +
        \end{bmatrix}\Bigg\}</math>
 +
|-
 +
|&nbsp; &nbsp; &nbsp; &nbsp; and a basis for the eigenspace corresponding to the eigenvalue &nbsp;<math style="vertical-align: -1px">4</math>&nbsp; is
 +
|-
 +
|
 +
::::<math>\Bigg\{\begin{bmatrix}
 +
          0 \\
 +
          1 \\
 +
          1
 +
        \end{bmatrix}\Bigg\}.</math>
 
|}
 
|}
 
[[031_Review_Part_3|'''<u>Return to Sample Exam</u>''']]
 
[[031_Review_Part_3|'''<u>Return to Sample Exam</u>''']]

Revision as of 09:34, 13 October 2017

Let  

Use the Diagonalization Theorem to find the eigenvalues of    and a basis for each eigenspace.


Foundations:  
Diagonalization Theorem
An    matrix    is diagonalizable if and only if    has    linearly independent eigenvectors.
In fact,    with    a diagonal matrix, if and only if the columns of    are    linearly
independent eigenvectors of    In this case, the diagonal entries of    are eigenvalues of    that
correspond, respectively , to the eigenvectors in  


Solution:

Step 1:  
Since
is a diagonal matrix, the eigenvalues of    are    and    by the Diagonalization Theorem.
Step 2:  
By the Diagonalization Theorem, a basis for the eigenspace corresponding
to the eigenvalue    is
and a basis for the eigenspace corresponding to the eigenvalue  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 4}   is
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Bigg\{\begin{bmatrix} 0 \\ 1 \\ 1 \end{bmatrix}\Bigg\}.}


Final Answer:  
        The eigenvalues of  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A}   are  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3}   and  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 4.}  
        A basis for the eigenspace corresponding
        to the eigenvalue  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3}   is
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Bigg\{\begin{bmatrix} 3 \\ 0 \\ 1 \end{bmatrix},\begin{bmatrix} -1 \\ -3\\ 0 \end{bmatrix}\Bigg\}}
        and a basis for the eigenspace corresponding to the eigenvalue  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 4}   is
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Bigg\{\begin{bmatrix} 0 \\ 1 \\ 1 \end{bmatrix}\Bigg\}.}

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