Difference between revisions of "031 Review Part 2, Problem 9"
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 1: | !Step 1: | ||
| + | |- | ||
| + | |Using the facts in the Foundations section, we have | ||
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{1} & = & \displaystyle{\text{det }(I)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\text{det } (AA^T)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{(\text{det }A)(\text{det } A^T)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{(\text{det }A)(\text{det } A)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{(\text{det }A)^2.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 2: | !Step 2: | ||
| + | |- | ||
| + | |Taking the square root of both sides of the equation | ||
|- | |- | ||
| | | | ||
| + | ::<math>(\text{det }A)^2=1,</math> | ||
| + | |- | ||
| + | |we obtain <math style="vertical-align: -1px">\text{det }A=\pm 1.</math> | ||
|} | |} | ||
| Line 33: | Line 51: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | | | + | | <math>\text{det }A=\pm 1</math> |
|} | |} | ||
[[031_Review_Part_2|'''<u>Return to Sample Exam</u>''']] | [[031_Review_Part_2|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 19:30, 10 October 2017
If is an matrix such that what are the possible values of
| Foundations: |
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| Recall: |
| 1. |
| 2. |
| 3. |
Solution:
| Step 1: |
|---|
| Using the facts in the Foundations section, we have |
|
|
| Step 2: |
|---|
| Taking the square root of both sides of the equation |
|
|
| we obtain |
| Final Answer: |
|---|