Difference between revisions of "009C Sample Final 2, Problem 5"

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|Since &nbsp; <math style="vertical-align: -14px">c_n=\frac{f^{(n)}(a)}{n!},</math>&nbsp; we have
 
|Since &nbsp; <math style="vertical-align: -14px">c_n=\frac{f^{(n)}(a)}{n!},</math>&nbsp; we have
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|&nbsp; &nbsp; &nbsp; &nbsp;<math>T_0=\frac{\sqrt{2}}{2}</math>
 
|&nbsp; &nbsp; &nbsp; &nbsp;<math>T_0=\frac{\sqrt{2}}{2}</math>

Revision as of 17:21, 10 March 2017

Find the Taylor Polynomials of order 0, 1, 2, 3 generated by    at  

Foundations:  
The Taylor polynomial of     at     is

        where


Solution:

Step 1:  
Let  
First, we make a table to find the coefficients of the Taylor polynomial.
Step 2:  
Let    be the Taylor polynomial of order  
Since     we have
 
       
       Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle T_{1}={\frac {\sqrt {2}}{2}}-{\frac {\sqrt {2}}{2}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}}
       
       Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle T_{3}={\frac {\sqrt {2}}{2}}-{\frac {\sqrt {2}}{2}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}-{\frac {\sqrt {2}}{4}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}^{2}+{\frac {\sqrt {2}}{12}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}^{3}.}


Final Answer:  
       Let    be the Taylor polynomial of order  
 
       
       Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle T_{1}={\frac {\sqrt {2}}{2}}-{\frac {\sqrt {2}}{2}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}}
       
       

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