Difference between revisions of "009A Sample Final 3, Problem 5"
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Kayla Murray (talk | contribs) |
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!Step 1: | !Step 1: | ||
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− | | | + | |We use implicit differentiation to find the derivative of the given curve. |
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− | | | + | |Using the product and chain rule, we get |
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− | | | + | | <math>3x^2+3y^2y'=2y+2xy'.</math> |
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− | | | + | |We rearrange the terms and solve for <math style="vertical-align: -5px">y'.</math> |
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+ | |Therefore, | ||
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+ | | <math>3x^2-2y=2xy'-3y^2y'</math> | ||
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+ | |and | ||
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+ | | <math>y'=\frac{3x^2-2y}{2x-3y^2}.</math> | ||
|} | |} | ||