Difference between revisions of "009A Sample Final 3, Problem 4"

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<span class="exam"> Discuss, without graphing, if the following function is continuous at <math>x=0.</math>
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<span class="exam"> Discuss, without graphing, if the following function is continuous at &nbsp;<math style="vertical-align: 0px">x=0.</math>
  
 
::<math>f(x) = \left\{
 
::<math>f(x) = \left\{
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</math>
 
</math>
  
<span class="exam">If you think <math>f</math> is not continuous at <math>x=0,</math> what kind of discontinuity is it?
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<span class="exam">If you think &nbsp;<math style="vertical-align: -4px">f</math>&nbsp; is not continuous at &nbsp;<math style="vertical-align: -4px">x=0,</math>&nbsp; what kind of discontinuity is it?
  
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"

Revision as of 11:39, 6 March 2017

Discuss, without graphing, if the following function is continuous at  

If you think    is not continuous at  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=0,}   what kind of discontinuity is it?

Foundations:  
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)}   is continuous at  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=a}   if
       Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow a^+}f(x)=\lim_{x\rightarrow a^-}f(x)=f(a).}


Solution:

Step 1:  
Step 2:  


Final Answer:  

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