Difference between revisions of "009C Sample Final 2, Problem 2"
Kayla Murray (talk | contribs) |
Kayla Murray (talk | contribs) |
||
| Line 28: | Line 28: | ||
!Step 1: | !Step 1: | ||
|- | |- | ||
| − | | | + | |Let <math>a_n</math> be the <math>n</math>th term of this sum. |
| + | |- | ||
| + | |We notice that | ||
| + | |- | ||
| + | |  , <math>\frac{a_2}{a_1}=\frac{-2}{4},~\frac{a_3}{a_2}=\frac{1}{-2},</math> and <math>\frac{a_4}{a_2}=\frac{-1}{2}.</math> | ||
|- | |- | ||
| − | | | + | |So, this is a geometric series with <math>r=\frac{-1}{2}.</math> |
|- | |- | ||
| − | | | + | |Since <math>|r|<1,</math> this series converges. |
|} | |} | ||
| Line 38: | Line 42: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |Hence, the sum of this geometric series is |
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{\frac{a_1}{1-r}} & = & \displaystyle{\frac{4}{1-(-\frac{1}{2})}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\frac{4}{\frac{3}{2}}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\frac{8}{3}.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
| Line 67: | Line 78: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | | '''(a)''' | + | | '''(a)''' <math>\frac{8}{3}</math> |
|- | |- | ||
| '''(b)''' | | '''(b)''' | ||
|} | |} | ||
[[009C_Sample_Final_2|'''<u>Return to Sample Exam</u>''']] | [[009C_Sample_Final_2|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 18:49, 4 March 2017
For each of the following series, find the sum if it converges. If it diverges, explain why.
(a)
(b)
| Foundations: |
|---|
| 1. The sum of a convergent geometric series is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{a}{1-r}} |
| where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r} is the ratio of the geometric series |
| and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a} is the first term of the series. |
| 2. The Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n} th partial sum, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s_n} for a series Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{n=1}^\infty a_n } is defined as |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s_n=\sum_{i=1}^n a_i.} |
Solution:
(a)
| Step 1: |
|---|
| Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a_n} be the Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n} th term of this sum. |
| We notice that |
|  , Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{a_2}{a_1}=\frac{-2}{4},~\frac{a_3}{a_2}=\frac{1}{-2},} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{a_4}{a_2}=\frac{-1}{2}.} |
| So, this is a geometric series with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r=\frac{-1}{2}.} |
| Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |r|<1,} this series converges. |
| Step 2: |
|---|
| Hence, the sum of this geometric series is |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\frac{a_1}{1-r}} & = & \displaystyle{\frac{4}{1-(-\frac{1}{2})}}\\ &&\\ & = & \displaystyle{\frac{4}{\frac{3}{2}}}\\ &&\\ & = & \displaystyle{\frac{8}{3}.} \end{array}} |
(b)
| Step 1: |
|---|
| Step 2: |
|---|
| Final Answer: |
|---|
| (a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{8}{3}} |
| (b) |