Difference between revisions of "009C Sample Final 2, Problem 9"
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| − | | | + | |How do you calculate <math style="vertical-align: -5px">y'</math> for a polar curve <math style="vertical-align: -5px">r=f(\theta)?</math> |
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| + | Since <math style="vertical-align: -5px">x=r\cos(\theta),~y=r\sin(\theta),</math> we have | ||
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| + | <math>y'=\frac{dy}{dx}=\frac{\frac{dr}{d\theta}\sin\theta+r\cos\theta}{\frac{dr}{d\theta}\cos\theta-r\sin\theta}.</math> | ||
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'''Solution:''' | '''Solution:''' | ||
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| − | | | + | |Insert sketch of graph |
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Revision as of 20:38, 4 March 2017
A curve is given in polar coordinates by
(a) Sketch the curve.
(b) Compute
(c) Compute
| Foundations: |
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| How do you calculate for a polar curve |
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Since we have |
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Solution:
| (a) |
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| Insert sketch of graph |
(b)
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| Step 2: |
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(c)
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| Step 2: |
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| Final Answer: |
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| (a) |
| (b) |
| (c) |