Difference between revisions of "009B Sample Final 3, Problem 5"
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!Step 1: | !Step 1: | ||
|- | |- | ||
| − | |First, we use the identity <math>\sin^2 x=1-\cos^2 x</math> to get | + | |First, we use the identity <math style="vertical-align: -1px">\sin^2 x=1-\cos^2 x</math> to get |
|- | |- | ||
| <math>\begin{array}{rcl} | | <math>\begin{array}{rcl} | ||
| Line 67: | Line 67: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
| − | |Now, we use <math>u</math>-substitution. | + | |Now, we use <math style="vertical-align: 0px">u</math>-substitution. |
|- | |- | ||
| − | |Let <math>u=\cos(x)</math> | + | |Let <math style="vertical-align: -5px">u=\cos(x).</math> Then, <math style="vertical-align: -5px">du=-\sin(x)dx</math> and <math style="vertical-align: -5px">-du=\sin(x)dx.</math> |
|- | |- | ||
|Therefore, we have | |Therefore, we have | ||
Revision as of 16:11, 28 February 2017
Find the following integrals.
(a)
(b)
| Foundations: |
|---|
| 1. Integration by parts tells us that |
| 2. Since we have |
Solution:
(a)
| Step 1: |
|---|
| To calculate this integral, we use integration by parts. |
| Let and |
| Then, and |
| Therefore, we have |
| Step 2: |
|---|
| Then, we integrate to get |
(b)
| Step 1: |
|---|
| First, we use the identity to get |
| Step 2: |
|---|
| Now, we use Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u} -substitution. |
| Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u=\cos(x).} Then, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle du=-\sin(x)dx} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -du=\sin(x)dx.} |
| Therefore, we have |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\int \sin^3(x)\cos^2(x)~dx} & = & \displaystyle{\int (-1)(1-u^2)u^2~du}\\ &&\\ & = & \displaystyle{\int u^4-u^2~du}\\ &&\\ & = & \displaystyle{\frac{u^5}{5}-\frac{u^3}{3}+C}\\ &&\\ & = & \displaystyle{\frac{\cos^5 x}{5}-\frac{\cos^3 x}{3}+C.} \end{array}} |
| Final Answer: |
|---|
| (a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x\sin x +\cos x+C} |
| (b) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{\cos^5 x}{5}-\frac{\cos^3 x}{3}+C} |