Difference between revisions of "009C Sample Midterm 1, Problem 1"
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!Step 1: | !Step 1: | ||
|- | |- | ||
− | | | + | |First, we notice that |
|- | |- | ||
− | | | + | | <math>\lim_{n\rightarrow \infty} \ln n =\infty</math> |
+ | |- | ||
+ | |and | ||
+ | |- | ||
+ | | <math>\lim_{n\rightarrow \infty} n=\infty.</math> | ||
+ | |- | ||
+ | |Therefore, the limit has the form <math>\frac{\infty}{\infty},</math> | ||
+ | |- | ||
+ | |which means we can use L'Hopital's Rule to calculate this limit. | ||
|} | |} | ||
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!Step 2: | !Step 2: | ||
|- | |- | ||
− | | | + | |First, we switch to the variable <math>x</math> so we have functions and |
|- | |- | ||
− | | | + | |can take derivatives. Thus, using L'Hopital's Rule, we have |
+ | |- | ||
+ | | <math>\begin{array}{rcl} | ||
+ | \displaystyle{\lim_{n\rightarrow \infty} \frac{\ln n}{n}} & = & \displaystyle{\lim_{x\rightarrow \infty} \frac{\ln x}{x}}\\ | ||
+ | &&\\ | ||
+ | & \overset{L'H}{=} & \displaystyle{\lim_{x\rightarrow \infty} \frac{\big(\frac{1}{x}\big)}{1}}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{0.} | ||
+ | \end{array}</math> | ||
|} | |} | ||
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!Final Answer: | !Final Answer: | ||
|- | |- | ||
− | | | + | | <math>0</math> |
− | |||
− | |||
|} | |} | ||
[[009C_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']] | [[009C_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']] |
Revision as of 13:15, 12 February 2017
Does the following sequence converge or diverge?
If the sequence converges, also find the limit of the sequence.
Be sure to jusify your answers!
Foundations: |
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L'Hôpital's Rule |
Suppose that and are both zero or both |
If is finite or |
then |
Solution:
Step 1: |
---|
First, we notice that |
and |
Therefore, the limit has the form |
which means we can use L'Hopital's Rule to calculate this limit. |
Step 2: |
---|
First, we switch to the variable so we have functions and |
can take derivatives. Thus, using L'Hopital's Rule, we have |
Final Answer: |
---|