Difference between revisions of "009B Sample Final 1, Problem 4"

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!Step 2:  
 
!Step 2:  
 
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|Now, for the one remaining integral, we use <math>u</math>-substitution.
 
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|Let <math>u=e^x</math>. Then, <math>du=e^xdx</math>. So, we have
 
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|<math>\int e^x(x+\sin(e^x))~dx=xe^x-e^x+\int \sin(u)~du=xe^x-e^x-\cos(u)+C=xe^x-e^x-\cos(e^x)+C</math>.
 
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!Final Answer: &nbsp;  
 
!Final Answer: &nbsp;  
 
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|'''(a)'''
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|'''(a)''' <math>xe^x-e^x-\cos(e^x)+C</math>
 
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|'''(b)'''  
 
|'''(b)'''  

Revision as of 08:36, 2 February 2016

Compute the following integrals.

a)

b)

c)


Foundations:  
Review -substitution and
Integration by parts

Solution:

(a)

Step 1:  
We first distribute to get .
Now, for the first integral on the right hand side of the last equation, we use integration by parts.
Let and . Then, and . So, we have
Step 2:  
Now, for the one remaining integral, we use -substitution.
Let . Then, . So, we have
.

(b)

Step 1:  
Step 2:  
Step 3:  

(c)

Step 1:  
Step 2:  
Final Answer:  
(a)
(b)
(c)

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