Difference between revisions of "009B Sample Final 1, Problem 1"
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!Foundations: | !Foundations: | ||
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− | | | + | |Link to Riemann sums page |
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!Step 1: | !Step 1: | ||
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− | | | + | |To find the actual area of the region, we need to calculate |
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− | | | + | |<math>\int_{-3}^3 2(-x^2+9)~dx</math> |
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!Step 2: | !Step 2: | ||
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− | | | + | |We integrate to get |
− | |||
− | |||
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+ | ::<math>\begin{array}{rcl} | ||
+ | \displaystyle{\int_{-3}^3 2(-x^2+9)~dx} & = & \displaystyle{2\bigg(\frac{-x^3}{3}+9x\bigg)\bigg|_{-3}^3}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{2\bigg(\frac{-3^3}{3}+9\times 3\bigg)-2\bigg(\frac{-(-3)^3}{3}+9(-3)\bigg)}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{2(-9+27)-2(9-27)}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{2(18)-2(-18)}\\ | ||
+ | &&\\ | ||
+ | & = & \displaystyle{72}\\ | ||
+ | \end{array}</math> | ||
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|'''(b)''' | |'''(b)''' | ||
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− | |'''(c)''' | + | |'''(c)''' <math>72</math> |
|} | |} | ||
[[009B_Sample_Final_1|'''<u>Return to Sample Exam</u>''']] | [[009B_Sample_Final_1|'''<u>Return to Sample Exam</u>''']] |
Revision as of 17:52, 4 February 2016
Consider the region bounded by the following two functions:
- and
a) Using the lower sum with three rectangles having equal width , approximate the area.
b) Using the upper sum with three rectangles having equal width, approximate the area.
c) Find the actual area of the region.
Foundations: |
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Link to Riemann sums page |
Solution:
(a)
Step 1: |
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Step 2: |
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(b)
Step 1: |
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Step 2: |
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Step 3: |
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(c)
Step 1: |
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To find the actual area of the region, we need to calculate |
Step 2: |
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We integrate to get |
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Final Answer: |
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(a) |
(b) |
(c) |