Difference between revisions of "009C Sample Final 1, Problem 2"
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Kayla Murray (talk | contribs) (Created page with "{| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundations: |- | |} '''Solution:''' '''(a)''' {| class="mw-collapsible mw-collapsed" style = "te...") |
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| + | <span class="exam"> Find the sum of the following series: | ||
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| + | ::<span class="exam">a) <math>\sum_{n=0}^{\infty} (-2)^ne^{-n}</math> | ||
| + | ::<span class="exam">b) <math>\sum_{n=1}^{\infty} \bigg(\frac{1}{2^n}-\frac{1}{2^{n+1}}\bigg)</math> | ||
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Foundations: | !Foundations: | ||
Revision as of 19:07, 1 February 2016
Find the sum of the following series:
- a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{n=0}^{\infty} (-2)^ne^{-n}}
- b) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{n=1}^{\infty} \bigg(\frac{1}{2^n}-\frac{1}{2^{n+1}}\bigg)}
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Solution:
(a)
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(b)
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(c)
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| Final Answer: |
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| (a) |
| (b) |
| (c) |