Difference between revisions of "009B Sample Midterm 2, Problem 1"

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!Step 1:    
 
!Step 1:    
 
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|Since our interval is <math>[1,5]</math> and we are using 4 rectangles, each rectangle has width 1. So, the left-endpoint Riemann sum is
 
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|<math>1(f(1)+f(2)+f(3)+f(4))</math>.  
 
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!Step 2: &nbsp;
 
!Step 2: &nbsp;
 
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|Thus, the left-endpoint Riemann sum is
 
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|<math>1(f(1)+f(2)+f(3)+f(4))=\bigg(1+\frac{1}{4}+\frac{1}{9}+{1}{16}\bigg)=\frac{205}{144}</math>. 
 
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!Final Answer: &nbsp;  
 
!Final Answer: &nbsp;  
 
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|'''(a)'''  
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|'''(a)''' <math>\frac{205}{144}</math>
 
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|'''(b)'''  
 
|'''(b)'''  
 
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[[009B_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']]
 
[[009B_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']]

Revision as of 14:22, 31 January 2016

Consider the region bounded by and the -axis.

a) Use four rectangles and a Riemann sum to approximate the area of the region . Sketch the region and the rectangles and indicate your rectangles overestimate or underestimate the area of .
b) Find an expression for the area of the region as a limit. Do not evaluate the limit.


Foundations:  
Link to Riemann sums page

Solution:

(a)

Step 1:  
Since our interval is and we are using 4 rectangles, each rectangle has width 1. So, the left-endpoint Riemann sum is
.
Step 2:  
Thus, the left-endpoint Riemann sum is
.

(b)

Step 1:  
Step 2:  
Final Answer:  
(a)
(b)

Return to Sample Exam