Difference between revisions of "004 Sample Final A, Problem 8"

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! Foundations
 
! Foundations
 
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|If <math>f(x)=x^4+bx^3+cx^2+dx+e</math>, what does the rational roots tell us are the possible roots of <math>f(x)</math>?
 
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|Answer:
 
|Answer:
 
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|The rational roots tells us that the possible roots of <math>f(x)</math> are <math>\pm k</math> where <math>k</math> is a divisor of <math>e</math>.
 
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! Step 1:
 
! Step 1:
 
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|By the rational roots test, the possible roots of <math>f(x)</math> are <math>\pm\{1,2,3,4,6,8,12,24\}</math>.
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! Step 2:
 
! Step 2:
 
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|Using synthetic division, we test 1 as a root of <math>f(x)</math>. We get a remainder of 0. So, we have that 1 is a root of <math>f(x)</math>.
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|By synthetic division, <math>f(x)=(x-1)(x^3-3x^2-10x+24)</math>.
 
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! Step 3:
 
! Step 3:
 
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|Using synthetic division on <math>x^3-3x^2-10x+24</math>, we test 2 as a root of this function. We get a remainder of 0. So, we have that 2 is a root of <math> x^3-3x^2-10x+24</math>.
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|By synthetic division, <math>x^3-3x^2-10x+24=(x-2)(x^2-x-12)</math>.
 
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! Step 4:
 
! Step 4:
 
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|Thus, <math>f(x)=(x-1)(x-2)(x^2-x-12)=(x-1)(x-2)(x-4)(x+3)</math>.
 
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|The zeros of <math>f(x)</math> are <math>1,2,4,-3</math>.
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! Final Answer:
 
! Final Answer:
 
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|The possible roots of <math>f(x)</math> are <math>\pm\{1,2,3,4,6,8,12,24\}</math>.
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|The zeros of <math>f(x)</math> are <math>1,2,4,-3</math>
 
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[[004 Sample Final A|<u>'''Return to Sample Exam</u>''']]
 
[[004 Sample Final A|<u>'''Return to Sample Exam</u>''']]

Latest revision as of 17:11, 4 May 2015

a) List all the possible rational zeros of the function
b) Find all the zeros, that is, solve

Foundations
If , what does the rational roots tell us are the possible roots of ?
Answer:
The rational roots tells us that the possible roots of are where is a divisor of .


Solution:

Step 1:
By the rational roots test, the possible roots of are .
Step 2:
Using synthetic division, we test 1 as a root of . We get a remainder of 0. So, we have that 1 is a root of .
By synthetic division, .
Step 3:
Using synthetic division on , we test 2 as a root of this function. We get a remainder of 0. So, we have that 2 is a root of .
By synthetic division, .
Step 4:
Thus, .
The zeros of are .
Final Answer:
The possible roots of are .
The zeros of are

Return to Sample Exam