Difference between revisions of "004 Sample Final A, Problem 9"
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Kayla Murray (talk | contribs) (Created page with "<span class="exam"> Graph the function. Give equations of any asymptotes, and list any intercepts. <math>y = \frac{6}{x^2 - x - 2}</math>") |
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<span class="exam"> Graph the function. Give equations of any asymptotes, and list any intercepts. <math>y = \frac{6}{x^2 - x - 2}</math> | <span class="exam"> Graph the function. Give equations of any asymptotes, and list any intercepts. <math>y = \frac{6}{x^2 - x - 2}</math> | ||
| + | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Foundations | ||
| + | |- | ||
| + | |What are the vertical asymptotes of <math>f(x)</math>? | ||
| + | |- | ||
| + | |Answer: | ||
| + | |- | ||
| + | |The vertical asymptotes are <math>x=a</math> where <math>f(a)</math> is undefined. | ||
| + | |} | ||
| + | |||
| + | |||
| + | Solution: | ||
| + | |||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 1: | ||
| + | |- | ||
| + | |Since <math>y=\frac{6}{(x-2)(x+1)}</math>, the vertical asymptotes are <math>x=2</math> and <math>x=-1</math>. | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 2: | ||
| + | |- | ||
| + | |The horizontal asymptote is <math>y=0</math>. | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 3: | ||
| + | |- | ||
| + | |There is no <math>x</math> intercept since <math>y\neq 0 </math> for any <math>x</math>. | ||
| + | |- | ||
| + | |Plugging in <math>x=0</math>, we get <math>y=-3</math>. So, the <math>y</math> intercept is (0,3) | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Final Answer: | ||
| + | |- | ||
| + | | The vertical asymptotes are <math>x=2</math> and <math>x=-1</math>. The horizontal asymptote is <math>y=0</math>. There is no <math>x</math> intercept and the <math>y</math> intercept is (0,3). | ||
| + | |} | ||
| + | |||
| + | [[004 Sample Final A|<u>'''Return to Sample Exam</u>''']] | ||
Latest revision as of 14:16, 11 May 2015
Graph the function. Give equations of any asymptotes, and list any intercepts.
| Foundations |
|---|
| What are the vertical asymptotes of ? |
| Answer: |
| The vertical asymptotes are where is undefined. |
Solution:
| Step 1: |
|---|
| Since , the vertical asymptotes are and . |
| Step 2: |
|---|
| The horizontal asymptote is . |
| Step 3: |
|---|
| There is no intercept since for any . |
| Plugging in , we get . So, the intercept is (0,3) |
| Final Answer: |
|---|
| The vertical asymptotes are and . The horizontal asymptote is . There is no intercept and the intercept is (0,3). |