Difference between revisions of "004 Sample Final A, Problem 3"
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Kayla Murray (talk | contribs) (Created page with "<span class="exam"> Solve. Provide your solution in interval notation. <math>\vert 4x + 7\vert \ge 5</math>") |
Kayla Murray (talk | contribs) |
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<span class="exam"> Solve. Provide your solution in interval notation. <math>\vert 4x + 7\vert \ge 5</math> | <span class="exam"> Solve. Provide your solution in interval notation. <math>\vert 4x + 7\vert \ge 5</math> | ||
| + | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Foundations | ||
| + | |- | ||
| + | |1) What is the solution to <math>|x|\geq 3</math>? | ||
| + | |- | ||
| + | |2) How do you write <math>x\geq 2</math> in interval notation? | ||
| + | |- | ||
| + | |Answer: | ||
| + | |- | ||
| + | |1) The solution is <math>x\geq 3</math> or <math>x\leq -3</math>. | ||
| + | |- | ||
| + | |2) <math>[2,\infty)</math> | ||
| + | |} | ||
| + | |||
| + | |||
| + | Solution: | ||
| + | |||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 1: | ||
| + | |- | ||
| + | |The inequality above means <math>4x+7\geq 5</math> or <math> 4x+7\leq -5</math>. | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 2: | ||
| + | |- | ||
| + | |Subtracting 7 from both sides of the inequalities, we get <math>4x\geq -2</math> or <math>4x\leq -12</math>. | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 3: | ||
| + | |- | ||
| + | |Dividing both sides of the inequalities by 4, we have <math>x\geq -\frac{1}{2}</math> or <math>x\leq -3</math>. | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Step 4: | ||
| + | |- | ||
| + | |Using interval notation, the solution is <math>(-\infty,-3]\cup [-\frac{1}{2},\infty)</math>. | ||
| + | |} | ||
| + | |||
| + | {|class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | ! Final Answer: | ||
| + | |- | ||
| + | |<math>(-\infty,-3]\cup [-\frac{1}{2},\infty)</math> | ||
| + | |} | ||
| + | |||
| + | [[004 Sample Final A|<u>'''Return to Sample Exam</u>''']] | ||
Latest revision as of 15:27, 4 May 2015
Solve. Provide your solution in interval notation.
| Foundations |
|---|
| 1) What is the solution to ? |
| 2) How do you write in interval notation? |
| Answer: |
| 1) The solution is or . |
| 2) |
Solution:
| Step 1: |
|---|
| The inequality above means or . |
| Step 2: |
|---|
| Subtracting 7 from both sides of the inequalities, we get or . |
| Step 3: |
|---|
| Dividing both sides of the inequalities by 4, we have or . |
| Step 4: |
|---|
| Using interval notation, the solution is . |
| Final Answer: |
|---|