Difference between revisions of "031 Review Part 2, Problem 9"
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Kayla Murray (talk | contribs) (Created page with "<span class="exam">Consider the matrix <math style="vertical-align: -31px">A= \begin{bmatrix} 1 & -4 & 9 & -7 \\ -1 & 2 & -4 & 1 \\...") |
Kayla Murray (talk | contribs) |
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| − | <span class="exam"> | + | <span class="exam">If <math style="vertical-align: 0px">A</math> is an <math style="vertical-align: 0px">n\times n</math> matrix such that <math style="vertical-align: -4px">AA^T=I,</math> what are the possible values of <math style="vertical-align: 0px">\text{det }A?</math> |
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Foundations: | !Foundations: | ||
|- | |- | ||
| − | | | + | |Recall: |
| + | |- | ||
| + | |'''1.''' <math style="vertical-align: -5px">\text{det }(AB)=(\text{det }A)(\text{det }B)</math> | ||
| + | |- | ||
| + | |'''2.''' <math style="vertical-align: 0px">\text{det }I=1</math> | ||
| + | |- | ||
| + | |'''3.''' <math style="vertical-align: 0px">\text{det }A^T=\text{det }A</math> | ||
|} | |} | ||
'''Solution:''' | '''Solution:''' | ||
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 1: | !Step 1: | ||
| + | |- | ||
| + | |Using the facts in the Foundations section, we have | ||
|- | |- | ||
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| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{1} & = & \displaystyle{\text{det }(I)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\text{det } (AA^T)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{(\text{det }A)(\text{det } A^T)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{(\text{det }A)(\text{det } A)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{(\text{det }A)^2.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 2: | !Step 2: | ||
| + | |- | ||
| + | |Taking the square root of both sides of the equation | ||
|- | |- | ||
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| + | ::<math>(\text{det }A)^2=1,</math> | ||
| + | |- | ||
| + | |we obtain <math style="vertical-align: -1px">\text{det }A=\pm 1.</math> | ||
|} | |} | ||
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!Final Answer: | !Final Answer: | ||
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| − | | | + | | <math>\text{det }A=\pm 1</math> |
|} | |} | ||
| − | [[031_Review_Part_2|'''<u>Return to | + | [[031_Review_Part_2|'''<u>Return to Review Problems</u>''']] |
Latest revision as of 13:40, 15 October 2017
If is an matrix such that what are the possible values of
| Foundations: |
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| Recall: |
| 1. |
| 2. |
| 3. |
Solution:
| Step 1: |
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| Using the facts in the Foundations section, we have |
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|
| Step 2: |
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| Taking the square root of both sides of the equation |
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|
| we obtain |
| Final Answer: |
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