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| | <span class="exam"> Be sure to jusify your answers! | | <span class="exam"> Be sure to jusify your answers! |
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| − | ::::::<math>a_n=\frac{\ln n}{n}</math>
| + | ::<math>a_n=\frac{\ln n}{n}</math> |
| | + | <hr> |
| | + | [[009C Sample Midterm 1, Problem 1 Solution|'''<u>Solution</u>''']] |
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| − | {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
| + | [[009C Sample Midterm 1, Problem 1 Detailed Solution|'''<u>Detailed Solution</u>''']] |
| − | !Foundations:
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| − | |'''L'Hôpital's Rule''' | |
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| − | Suppose that <math style="vertical-align: -11px">\lim_{x\rightarrow \infty} f(x)</math>  and <math style="vertical-align: -11px">\lim_{x\rightarrow \infty} g(x)</math>  are both zero or both <math style="vertical-align: -1px">\pm \infty .</math>
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| − | If <math style="vertical-align: -19px">\lim_{x\rightarrow \infty} \frac{f'(x)}{g'(x)}</math>  is finite or  <math style="vertical-align: -4px">\pm \infty ,</math>
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| − | then <math style="vertical-align: -19px">\lim_{x\rightarrow \infty} \frac{f(x)}{g(x)}\,=\,\lim_{x\rightarrow \infty} \frac{f'(x)}{g'(x)}.</math>
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| − | |}
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| − | '''Solution:'''
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| − | {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
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| − | !Step 1:
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| − | |First, we notice that
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| − | | <math>\lim_{n\rightarrow \infty} \ln n =\infty</math>
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| − | |and
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| − | | <math>\lim_{n\rightarrow \infty} n=\infty.</math>
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| − | |Therefore, the limit has the form <math style="vertical-align: -11px">\frac{\infty}{\infty},</math>
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| − | |which means we can use L'Hopital's Rule to calculate this limit.
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| − | |}
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| − | {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
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| − | !Step 2:
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| − | |First, we switch to the variable <math style="vertical-align: 0px">x</math> so we have functions and
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| − | |-
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| − | |can take derivatives. Thus, using L'Hopital's Rule, we have
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| − | | <math>\begin{array}{rcl}
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| − | \displaystyle{\lim_{n\rightarrow \infty} \frac{\ln n}{n}} & = & \displaystyle{\lim_{x\rightarrow \infty} \frac{\ln x}{x}}\\
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| − | &&\\
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| − | & \overset{L'H}{=} & \displaystyle{\lim_{x\rightarrow \infty} \frac{\big(\frac{1}{x}\big)}{1}}\\
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| − | &&\\
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| − | & = & \displaystyle{0.}
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| − | \end{array}</math>
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| − | |}
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| − | {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
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| − | !Final Answer:
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| − | | <math>0</math>
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| − | |}
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| | [[009C_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']] | | [[009C_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']] |
