Difference between revisions of "009C Sample Final 1, Problem 10"

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<span class="exam">A curve is given in polar parametrically by  
 
<span class="exam">A curve is given in polar parametrically by  
::::::<span class="exam"><math>x(t)=3\sin t</math>
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::<span class="exam"><math>x(t)=3\sin t</math>
::::::<span class="exam"><math>y(t)=4\cos t</math>
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::<span class="exam"><math>y(t)=4\cos t</math>
::::::<span class="exam"><math>0\leq t \leq 2\pi</math>
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::<span class="exam"><math>0\leq t \leq 2\pi</math>
  
<span class="exam">a) Sketch the curve.
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<span class="exam">(a) Sketch the curve.
  
<span class="exam">b) Compute the equation of the tangent line at <math>t_0=\frac{\pi}{4}</math>.
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<span class="exam">(b) Compute the equation of the tangent line at &nbsp;<math style="vertical-align: -14px">t_0=\frac{\pi}{4}</math>.
  
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<hr>
!Foundations: &nbsp;
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[[009C Sample Final 1, Problem 10 Solution|'''<u>Solution</u>''']]
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'''Solution:'''
 
  
'''(a)'''
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[[009C Sample Final 1, Problem 10 Detailed Solution|'''<u>Detailed Solution</u>''']]
  
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!Step 1: &nbsp;
 
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!Step 2: &nbsp;
 
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'''(b)'''
 
 
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!Step 1: &nbsp;
 
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!Step 2: &nbsp;
 
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!Step 3: &nbsp;
 
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!Final Answer: &nbsp;
 
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|'''(a)'''
 
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|'''(b)''' 
 
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[[009C_Sample_Final_1|'''<u>Return to Sample Exam</u>''']]
 
[[009C_Sample_Final_1|'''<u>Return to Sample Exam</u>''']]

Latest revision as of 14:02, 3 December 2017

A curve is given in polar parametrically by

(a) Sketch the curve.

(b) Compute the equation of the tangent line at  .


Solution


Detailed Solution


Return to Sample Exam