Difference between revisions of "005 Sample Final A, Question 2"
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Line 32: | Line 32: | ||
<td align = "center"><math> x<-1 </math></td> | <td align = "center"><math> x<-1 </math></td> | ||
<td align = "center"><math> x=-1 </math></td> | <td align = "center"><math> x=-1 </math></td> | ||
− | <td align = "center"><math> -1<x< | + | <td align = "center"><math> -1<x<2 </math></td> |
− | <td align = "center"><math> x= | + | <td align = "center"><math> x=2 </math></td> |
− | <td align = "center"><math>x> | + | <td align = "center"><math>x>2</math></td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
− | <td align = "center"><math> | + | <td align = "center"><math> Sign:</math></td> |
<td align = "center"><math> (+) </math></td> | <td align = "center"><math> (+) </math></td> | ||
<td align = "center"><math> 0 </math></td> | <td align = "center"><math> 0 </math></td> |
Revision as of 10:43, 6 May 2015
Question Find the domain of the following function. Your answer should be in interval notation
Foundations: |
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1) What is the domain of ? |
2) How can we factor ? |
Answer: |
1) The domain is . The domain of is , but we have to remove zero from the domain since we cannot divide by 0. |
2) |
Step 1: |
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We start by factoring into |
Step 1: | ||||||||||||
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Since we cannot divide by zero, and we cannot take the square root of a negative number, we use a sign chart to determine when | ||||||||||||