Difference between revisions of "004 Sample Final A, Problem 16"

Revision as of 15:56, 3 May 2015

Solve. ${\sqrt {x-3}}+5=x$

Foundations
1) How do you solve for $x$ in the equation ${\sqrt {x}}=5$ ?
2) How do you find the zeros of $f(x)=x^{2}+x-6$ ?
Answer:
1) You square both sides of the equation to get $x=25$ .
2) You factor $f(x)=0$ to get $(x+3)(x-2)=0$ . From here, we solve to get $x=-3$ or $x=2$ .

Solution:

Step 1:

Step 2:

Final Answer:

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 ! Foundations
 |-
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+|1) How do you solve for <math> x </math> in the equation <math>\sqrt{x}=5 </math>?
+|-
+|2) How do you find the zeros of <math>f(x)=x^2+x-6</math>?
 |-
 |Answer:
 |-
-|
+|1) You square both sides of the equation to get <math>x=25</math>.
+|-
+|2) You factor <math>f(x)=0</math> to get <math>(x+3)(x-2)=0</math>. From here, we solve to get <math>x=-3 </math> or <math>x=2</math>.
 |}